Q1. On increasing the numerator of a fraction by 15% and decreasing its denominator by 8%, the fraction becomes \frac{15}{16}. What is the original fraction?
A \frac{5}{4}
B \frac{3}{4} Correct
C \frac{6}{5}
D \frac{7}{4}
Explanation
Let the original fraction be x/y. After the change, it becomes (1.15x)/(0.92y) = 15/16. Therefore x/y = (15/16) x (0.92/1.15). Since 0.92/1.15 = 92/115 = 4/5, the original fraction is (15/16) x (4/5) = 3/4. The fraction 5/4 is greater than the resulting adjusted value and cannot satisfy the equation. The fractions 6/5 and 7/4 are also too large after the numerator is raised and the denominator is lowered.