MCQ
Light reflection in plane mirrors MCQ - Practice Questions with Answers
Solve 2 Light reflection in plane mirrors questions for RAS/RPSC preparation.
Practice questions
Q1A ray of light is incident at an angle of incidence 15° on a plane mirror, as shown in the figure. The value of angle X is:
The angle of incidence is measured from the normal to the mirror, not from the mirror surface. If the incident ray makes 15° with the normal, then the same geometry leaves 90° - 15° = 75° with the plane mirror surface. Hence angle X, as indicated in the figure, is 75°. The values 45° and 65° do not follow from the complementary angle relation here. The value 85° would correspond to only a 5° angle with the normal, which is not the given incidence angle.
Q2A ray of light is incident on a plane mirror normal to its surface. The angle of incidence and the angle of reflection are:
The angle of incidence is measured between the incident ray and the normal to the reflecting surface. If the ray falls normally on a plane mirror, it travels along the normal itself, so the angle of incidence is 0°. By the law of reflection, the angle of reflection equals the angle of incidence; therefore the reflected ray also makes 0° with the normal and retraces the same path. Choices containing 90° confuse the normal with the mirror surface, so they do not match the definition of the angle.
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