Numerical: Percentage Applications MCQ — 15 Practice Questions with Answers

Explanation

First apply the discount because GST is charged on the discounted price. Discount = 15% of ₹8000 = ₹1200. Discounted price = 8000 − 1200 = ₹6800. GST = 18% of ₹6800 = 6800 × 18 ÷ 100 = ₹1224. Final amount payable = discounted price + GST = 6800 + 1224 = ₹8024. Hence the customer must pay ₹8024.

Explanation

Let the salary before the increase be x. A 25% increase means the new salary is 125% of x. Therefore, 125% of x = ₹45000, or 1.25x = 45000. Now x = 45000 ÷ 1.25 = 45000 × 100 ÷ 125. Since 125 × 360 = 45000 exactly, x = 36000. So Meena's monthly salary before the increase was ₹36000.

Explanation

Calculate each item separately using percentage of sales = sales × percentage ÷ 100. For item 1, 12.5% of ₹240000 = 240000 × 12.5 ÷ 100 = ₹30000. For item 2, 8% of ₹240000 = 240000 × 8 ÷ 100 = ₹19200. For item 3, a 15% rise means 115% of ₹240000, so new sales = 240000 × 115 ÷ 100 = ₹276000. Therefore the correct matching is 1: ₹30000, 2: ₹19200, 3: ₹276000.

Explanation

First convert both percentages into marks. Rakesh's marks = 68% of 500 = 500 × 68 ÷ 100 = 340. Suman's marks = 72% of 500 = 500 × 72 ÷ 100 = 360. The difference between their marks is 360 − 340 = 20. So the statements saying 340 marks, 360 marks, and a difference of 20 marks are correct. The statement that Rakesh scored 32 marks less is incorrect.

Explanation

Let the original price be ₹x. After a 20% increase, the new price is 120% of the original price. So, 120% of x = 960. This gives x × 120/100 = 960. Therefore, x = 960 × 100/120 = 960 ÷ 1.2 = 800. This is a reverse percentage question, so the increase must be undone by dividing by 120%. The original price was ₹800.