Q1. The population of a town is 6000. If the number of males increases by 8% and the number of females increases by 10%, the population will become 6500. Find the number of females in the town.
Explanation
Let the number of females be x, so males are 6000 - x. The total increase is 6500 - 6000 = 500. Hence 8% of males plus 10% of females equals 500: 0.08(6000 - x) + 0.10x = 500. This gives 480 - 0.08x + 0.10x = 500, so 0.02x = 20 and x = 1000. Counts such as 1200, 1100, and 1300 would make the increase more than 500, so they do not fit the given final population.
