MCQ
Data interpretation and statistics (mean, median, mode) MCQ - Practice Questions with Answers
Solve 10 Data interpretation and statistics (mean, median, mode) questions for RAS/RPSC preparation.
Practice questions
Q1Assertion (A): For a survey of favourite subjects, the mode can identify the most selected subject. Reason (R): Mode is the value or category that occurs most often, while mean and median are not calculated for category names. Choose the correct statement.
Mode is defined as the observation with the highest frequency and add that mode can be used for non-numerical data. A favourite-subject survey gives category names, not numerical values. The most selected subject is therefore the category with the highest frequency, which is the mode. Mean and median are not suitable for such subject names because they need numerical values or an ordered numerical set. The reason explains why mode is the correct measure here.
Q2Statement 1: Mode is decided by the frequency of a value, not by its magnitude. Statement 2: If all observations occur equally often, one middle value must still be called the mode. Which of the following is correct?
Mode is defined as the observation that occurs most often. Therefore, frequency decides the mode, not the size of the number. They also warn that if every observation occurs equally often, the data set has no mode; a candidate should not force one value to be the mode just because it lies near the middle. Thus the statement about frequency is correct, while the statement about forcing a middle value as mode is incorrect.
Q3A class group has 20 students with a mean score of 50 and another group has 30 students with a mean score of 60. What is the combined mean score?
When two groups have different sizes, the combined average must use the weighted mean formula. The total score of the first group is 20 x 50 = 1000, and the total score of the second group is 30 x 60 = 1800. The combined total is 2800 for 50 students. Therefore, the combined mean is 2800 / 50 = 56. The simple average 55 ignores the unequal group sizes.
Q4Match List I with List II. List I: 1. A 90° sector in a pie chart with total 1200 students 2. A bar graph where one grid division represents 10 units 3. Equal distances covered at 30 km per hour and 60 km per hour List II: a. Read the scale before using bar height b. Average speed is 40 km per hour c. 300 students
There are three separate rules. In a pie chart, sector value = sector angle / 360 x total, so 90 / 360 x 1200 = 300 students. For a bar graph, the scale must be read first because one grid division may represent 10 units or another value. For equal distances at 30 km per hour and 60 km per hour, total distance divided by total time gives 40 km per hour, not the simple mean 45. Thus the proper matching is pie sector with 300 students, bar graph with scale reading, and equal-distance travel with 40 km per hour.
Q5Pass percentage in a test increased from 60% to 75%. Which statement is incorrect?
Percentage-point change is distinct from percentage change. Moving from 60% to 75% gives a direct increase of 15 percentage points. But percentage change must use the old value as the base: (75 - 60) / 60 x 100 = 15 / 60 x 100 = 25%. Therefore, saying that the percentage increase is 15% confuses the direct percentage-point difference with the percentage change.
You've seen 5 of 10 sample questions
Unlimited practice on Data interpretation and statistics (mean, median, mode) comes with the RAS Test Series + Practice pack or Gate Pass.
More questions
6Find the median of the observations 30, 10, 60, 20, 50 and 40.
7Which value is the median of the observations 18, 12, 30, 15 and 21?
8In one group, 20 students have an average score of 50. In another group, 30 students have an average score of 60. What is the combined average score of all 50 students?
9A pass percentage rises from 60% to 75%. Which statement is incorrect?
10List I: 1. Sector angle in a pie chart 2. Full circle in a pie chart 3. Sector of 90 degrees when total is 1200 List II: a. 360 degrees b. 300 c. sector angle / 360 x total Choose the correct matching.