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MCQ

Simple and Compound Interest MCQ - Practice Questions with Answers

Solve 12 Simple and Compound Interest questions for RAS/RPSC preparation.

Practice questions

Q1A courier-locker caution deposit of ₹1,000 is charged 20% per annum, compounded half-yearly. By how much does one-year compound interest exceed one-year simple interest at the same nominal annual rate?

A ₹10
B ₹200
C ₹210
D ₹40
Explanation

At 20% per annum compounded half-yearly, each half-year rate is 10%, so one year has two conversion periods. The one-year gap is P(r/200)² = 1,000 × (20/200)² = 1,000 × 0.01 = ₹10. Checking: SI = ₹200 and CI = 1,000 × 1.1² − 1,000 = ₹210, so the difference is ₹10.

Q2A handloom cooperative's working-capital loan grows to ₹9,680 after 2 years and to ₹10,648 after 3 years under annual compounding. Simple interest on the original principal for 5 years at the same rate equals:

A ₹2,400
B ₹4,000
C ₹3,200
D ₹8,000
Explanation

The third-year growth factor is 10,648/9,680 = 1.1, so the rate is 10% per annum. The principal is 9,680/(1.1)² = 9,680/1.21 = ₹8,000. Simple interest for 5 years is then 8,000 × 10 × 5/100 = ₹4,000.

Q3The compound interest on a bakery-oven loan for 2 years at 10% per annum is ₹1,680. Simple interest on the same principal for 3 years at the same rate is:

A ₹2,400
B ₹2,520
C ₹3,360
D ₹1,600
Explanation

Two-year CI at 10% means P[(1.10)² − 1] = 1,680, so 0.21P = 1,680 and P = ₹8,000. Three-year SI on that principal is 8,000 × 10 × 3/100 = ₹2,400.

Q4A packaging-machine loan at 5% per annum has two-year compound interest exceeding two-year simple interest by ₹40. What is the principal?

A ₹1,600
B ₹16,000
C ₹800
D ₹8,000
Explanation

For 2 years, CI − SI = P(r/100)². So P = 40/(5/100)² = 40/0.0025 = ₹16,000. Checking: SI = ₹1,600 and CI = 16,000 × 1.05² − 16,000 = ₹1,640, so the excess is ₹40.

Q5On a warehouse security deposit, compound interest (yearly) exceeds simple interest by ₹1,920 over 3 years at 20% per annum. What is the deposit?

A ₹48,000
B ₹19,200
C ₹16,000
D ₹15,000
Explanation

For 3 years, CI − SI = P(r/100)²(3 + r/100). Substitute the given values: 1,920 = P(20/100)²(3 + 20/100) = P(0.04)(3.2) = 0.128P. Therefore P = 1,920/0.128 = 15,000. Checking: SI = 9,000 and CI = 15,000×1.2³ − 15,000 = 10,920, so the difference is ₹1,920.

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Unlimited practice on Simple and Compound Interest comes with the RAS Test Series + Practice pack or Gate Pass.

More questions

6When the excess of compound interest over simple interest for 2 years equals 1/64 of the principal, what is the annual rate of interest?

A12.5%
B8%
C16%
D25%

7A sum of ₹4,000 deposited for maintenance earns interest at 10% per annum. By how many rupees does three-year compound interest exceed three-year simple interest?

A₹120
B₹1,324
C₹124
D₹40

8On a grain-silo construction loan of ₹3,600, the two-year gap between compound and simple interest is ₹81. What annual rate was charged?

A15%
B9%
C7.5%
D22.5%

9₹6,000 placed in a bicycle-hire shop's savings scheme earns ₹1,440 as simple interest at 8% per annum. How many years did the deposit run?

A2.4 years
B4 years
C3 years
D2 years

10Solvent drums were financed so that the two-year difference between compound and simple interest at 4% per annum came to ₹4.80. Find the financed principal.

A₹120
B₹480
C₹3,000
D₹4,800

11A tool-hire deposit becomes thrice the principal in 10 years under simple interest. In how many years will it become five times the principal at the same rate?

A15 years
B25 years
C30 years
D20 years

12A cold-storage advance of ₹12,500 produces ₹3,000 simple interest in 4 years. At the same rate, the two-year compound-minus-simple interest gap is:

A₹36
B₹45
C₹90
D₹750

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