Q1. For the parametric curve x = t^2, y = t^3 - 3t with t != 0, the value of d^2y/dx^2 is
Explanation
Here dy/dt = 3t^2 - 3 and dx/dt = 2t, so dy/dx = 3(t^2-1)/(2t) = (3/2)(t - 1/t). Differentiating with respect to t gives (3/2)(1 + 1/t^2), and division by dx/dt = 2t gives d^2y/dx^2 = 3(t^2+1)/(4t^3).
