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Paper - II (xv) — Basics of communication MCQ — 44 Practice Questions with Answers

Paper - II (xv) — Basics of communication is a Networking & Web (Senior CI) topic in the RAS/RPSC syllabus. This page gathers exam-style Paper - II (xv) — Basics of communication multiple-choice questions with correct answers and explanations, so aspirants can test recall and revise frequently examined concepts.

Practice 44 Paper - II (xv) — Basics of communication multiple-choice questions with detailed answers and explanations. Ideal for RAS/RPSC exam preparation.

44 Questions Networking & Web (Senior CI)

Reviewed by: Aspirant Academy Editorial Team

Practice Questions

Q1. For a brief technical introduction to GSM radio access, which pairing is most accurate?

A Analog FM voice channels with no digital time-slot structure
B OFDMA with QAM only, mainly a fourth-generation packet radio interface
C Direct-sequence CDMA using a unique spreading code as the primary access method
D GMSK modulation with TDMA signalling on frequency-division duplex carriers Correct

Explanation

GSM is a 2G digital cellular system. Its radio access is typically introduced as GMSK modulation with TDMA signalling over paired frequency-division duplex carriers. Confusing GSM with CDMA is a common exam trap: GSM divides users into time slots on radio carriers, whereas CDMA separates users primarily through codes.

Q2. A uniform plane electromagnetic wave in free space travels in the +z direction. At a particular instant and point, its electric field is along +x. Which statement is correct?

A The magnetic field is along +z and E0/B0 = c.
B The magnetic field is along -y and B0/E0 = c.
C The magnetic field is along +y and B0/E0 = c.
D The magnetic field is along +y and E0/B0 = c. Correct

Explanation

In a plane electromagnetic wave propagating through free space, the electric field, magnetic field, and direction of propagation are mutually perpendicular. The direction of energy flow follows E × B, so +x crossed with +y gives +z. The amplitude relation is E0/B0 = c, the speed of light in free space.

Q3. In a linear delta modulator with step size Delta and sampling interval Ts, which condition most directly indicates slope-overload distortion for an input x(t)?

A The input amplitude is smaller than Delta for all time.
B The sampling frequency is exactly twice the highest message frequency.
C The maximum magnitude of dx(t)/dt exceeds Delta/Ts. Correct
D The quantizer has 256 output levels.

Explanation

Delta modulation transmits whether the reconstructed staircase should move up or down by a fixed step. During one sampling interval it can change only by Delta, so its maximum trackable slope is Delta/Ts. If the message slope exceeds that value, the staircase lags behind the input and slope-overload distortion appears. Increasing step size or sampling rate can reduce this particular error, though too large a step increases granular noise.

Q4. In a link budget, a cable section has input power 20 mW and output power 2 mW. Immediately after it, an amplifier provides +13 dB gain. Ignoring all other losses, what is the net effect of the two stages?

A -7 dB net loss, because the powers must be subtracted before converting to decibels.
B 0 dB net change, because any attenuation can be exactly cancelled only by an equal numerical amplifier gain in milliwatts.
C +23 dB net gain, because the power ratio 20 mW to 2 mW contributes +10 dB.
D +3 dB net gain, because the cable contributes -10 dB and the amplifier contributes +13 dB. Correct

Explanation

Attenuation is represented as a negative power gain when output power is less than input power. Here the cable ratio is 2/20 = 0.1, which is -10 dB using 10 log10(Pout/Pin). Cascaded dB values add algebraically, so -10 dB + 13 dB = +3 dB.

Q5. Which description most accurately captures wavelength division multiplexing in optical communication?

A An analogue waveform is represented by a staircase that changes one step per sample.
B Several users share one carrier by occupying different time slots.
C Several bit streams are separated by assigning orthogonal spreading codes on the same carrier.
D Multiple optical carrier wavelengths are combined onto one fibre and separated by wavelength-selective devices. Correct

Explanation

WDM is a frequency-domain multiplexing technique at optical frequencies: distinct data streams modulate different wavelengths, which are combined into the same fibre and later separated optically. It should not be confused with time slots in TDM or spreading codes in CDMA. This makes it a high-capacity fibre technique rather than a source-coding method.

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Frequently Asked Questions

How many Paper - II (xv) — Basics of communication MCQ questions are available?
There are 44 Paper - II (xv) — Basics of communication practice MCQs available on Aspirant Academy, with detailed answers and explanations for each question.
Are answers and explanations provided for Paper - II (xv) — Basics of communication MCQs?
Yes, every Paper - II (xv) — Basics of communication question comes with the correct answer and a detailed explanation to help you understand the underlying concept.
How is Paper - II (xv) — Basics of communication relevant to the RAS/RPSC exam?
Paper - II (xv) — Basics of communication falls under the Networking & Web (Senior CI) section of the RAS/RPSC syllabus. It is a frequently tested area and regular practice with these MCQs will strengthen your preparation.
Can I practice Paper - II (xv) — Basics of communication questions in Hindi?
Yes, Aspirant Academy offers bilingual support. You can practice Paper - II (xv) — Basics of communication MCQs in both English and Hindi, including questions, options, and explanations.

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