Q1. Number of neutrons in ⁵⁶₂₆Fe will be
Explanation
In nuclide notation, the mass number equals protons plus neutrons, and the atomic number equals protons. For ⁵⁶₂₆Fe, neutrons = 56 - 26 = 30. Therefore, option C is correct.
Science and Pedagogy is a Science Part-III Teaching Methods (Sr Teacher) topic in the RAS/RPSC syllabus. This page gathers exam-style Science and Pedagogy multiple-choice questions with correct answers and explanations, so aspirants can test recall and revise frequently examined concepts.
Practice 148 Science and Pedagogy multiple-choice questions with detailed answers and explanations. Ideal for RAS/RPSC exam preparation.
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Q1. Number of neutrons in ⁵⁶₂₆Fe will be
Explanation
In nuclide notation, the mass number equals protons plus neutrons, and the atomic number equals protons. For ⁵⁶₂₆Fe, neutrons = 56 - 26 = 30. Therefore, option C is correct.
Q2. Which of the following element is chalcogen?
Explanation
Chalcogens are Group 16 elements of the periodic table. Tellurium has the symbol Te and belongs to Group 16, while At, Pb and Tl do not belong to this group. Therefore, option C is correct.
Q3. Antifertility drug is :
Explanation
Antifertility drugs are used as oral contraceptives, and ethynylestradiol, also called novestrol, is listed as a synthetic estrogen example in this group. Aspartame is an artificial sweetener, soframicine is an antimicrobial preparation, and prontosil is a sulfa drug, so C is the correct answer.
Q4. Select the option from the following sets (i to iv) which is not permissible for an electron in an atom - (i) n=2, l=1, m=0, s = + ½ (ii) n=3, l=3, m=-3, s= + ½ (iii) n=3, l=2, m=-2, s= 1 (iv) n=4, l=3, m=-2, s= + ½
Explanation
For an electron in an atom, l can have values from 0 to n−1, m can range from −l to +l, and the spin quantum number can only be +1/2 or −1/2. Set (ii) is impossible because n = 3 cannot have l = 3, and set (iii) is impossible because spin cannot be 1. Hence D is correct.
Q5. For Z = PV/nRT, Z is known as :
Explanation
For real gases, Z = PV/nRT is called the compressibility factor. It measures deviation from ideal gas behaviour, for which Z equals 1 under ideal conditions. Therefore C is correct.
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